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If three coin are tossed and E be the event to getting at least one head, then n(E) will be –(A) 6(B) 3(C) 4(D) 8 |
Answer» Answer is (C) 4 S = {HHH, HHT, HTH, HTT, THH, THT, TTH, ITT) n(E) = 4 |
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