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if TP and TQ are the two tangents to a circle with Centre O such that angle PTQ= 47 degree then find angle POQ |
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Answer» -STEP explanation:Given, ∠POQ=110 ∘ We KNOW,∠OPT=∠OQT=90 (Angle between the tangent and the radial line at the POINT of INTERSECTION of the tangent at the CIRCLE)Now, in quadrilateral POQTSum of angles=360∠OPT+∠OQT+∠PTQ+∠POQ=360 ∘ 90+90+∠PTQ+110=360∠PTQ=360−290∠PTQ=70° |
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