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If TP and TQ are the two tangents to a circle with centre O, such that ∠PTQ = 47°, then find ∠POQ. |
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Answer» Thus ∠POQ=133°Step-by-step explanation:in the FIG PT and QT are tangents and O is the centreNow in the QUADRILATERAL POQT∠P=∠Q= 90Thus ∠P+∠Q+∠POQ+∠PTQ=36090+90+x+47=360x=360-180-47=133x=133Thus ∠POQ=133° |
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