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If two capacitors C_(1) and C_(2) are connected in a parallel combination then the equivalent capacitanceis 10 mu F . If both the capacitors are connected across a l V battery, then energy stored in C_(2) is 4 times of that in C_(1). The equivalent capacitance if they are connected in series is |
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Answer» `16 MU F `  For parallel connection and from QUESTION `4 ((1)/(2) C_(1)^(2))= (1)/(2) C_(2)V^(2)` `:. 4 C_(1)= C_(2)` By using EQUATION (2) in equation (1), `C_(1) + 4 C_(1) = 10 mu F ` ` :. 5 C_(1) = 10 mu F` `:. C_(1) = 2 mu F ` From equation (2) `C_(2) = 4 C_(1)` `= 4xx2` `= 8 mu F ` Now, equivalent capacitance of series connection of `2mu`F and `8mu`F `C = (C_(1)C_(2))/(C_(1)+C_(2))=(2xx8)/(2+8)= (16)/(10)` `= 1.6 mu F ` |
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