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If two charged particles each of charge q mass m are connected to the ends of a rigid massless rod and is rotated about an axis passing through the centre and bot to length. Then find the ratio of magnetic moment to angular momentum

Answer»

SOLUTION :`M=niA=2xxq/Tpi(l/2)^(2)`
`=2xx(qomega)/(2pi)(pil^(2))/4=(qomegal^(2))/4`
`L=2(MR^(2)OMEGA)=2(m(l^(2))/4OMEGA)=(ml^(2)omega)/2, M/L=q/(2M)`


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