If two different dice are rolled together, the probability of getting

1.	If two different dice are rolled together, the probability of getting an even number on both dice, isA. \(\frac{1}{36}\)B. \(\frac{1}{2}\)C. \(\frac{1}{6}\)D.\(\frac{1}{4}\)
Answer» Total numbers of elementary events are: 6 x 6 = 36 Let E be the event of getting an even number on both the dice Favorable outcomes are: (2,2) , (2,4), (2,6), (4,2), (4,4), (4,6), (6,2), (6,4), (6,6) Numbers of favorable outcomes are = 9 P (getting even number on both dice) = P (E) = \(\frac{9}{36}\) = \(\frac{1}{4}\)

If two different dice are rolled together, the probability of getting an even number on both dice, isA. \(\frac{1}{36}\)B. \(\frac{1}{2}\)C. \(\frac{1}{6}\)D.\(\frac{1}{4}\)

Answer»

Total numbers of elementary events are: 6 x 6 = 36

Let E be the event of getting an even number on both the dice

Favorable outcomes are: (2,2) , (2,4), (2,6), (4,2), (4,4), (4,6), (6,2), (6,4), (6,6)

Numbers of favorable outcomes are = 9

P (getting even number on both dice) = P (E) = \(\frac{9}{36}\) = \(\frac{1}{4}\)

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If two different dice are rolled together, the probability of getting an even number on both dice, isA. \(\frac{1}{36}\)B. \(\frac{1}{2}\)C. \(\frac{1}{6}\)D.\(\frac{1}{4}\)

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