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If two opposite electric charges having same magnitude are 10 cm away from each other, they experience 0.9N attractive force then magnitude of electric charges will be...... |
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Answer» `1pC` `F = 0.9 N, k = 9 XX 10^(9) SI, gamma = 10 cm = 10^(-2) cm` `therefore Q^(2) = (Fr^(2))/k = (0.9 xx 10^(-2))/(9 xx 10^(9)) = 10^(-12)` `therefore q = 1 xx 10^(-6) C, therefore q = 1muC` |
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