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If two SHMs are repersented by `y_(1) = 10 sin (4 pi + pi//2)` and `y_(2) = 5 (sin 2 pi t +sqrt 8 cos 2 pi t)`, compare their amplitudes . |
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Answer» For the equation `y_(1) = 10 sin (4 pi t + pi//2)`, the amplitude `a_(1) = 10 units` For equation `y_(2) = 5 [sin 2 pi t + sqrt8 cos 2 pi t]` multplying and dividing by `sqrt(1 + 8) = 3` `y_(2) = [15 sin (2 pi t) xx (1)/(3) + cos (2 pi t) (sqrt8)/(3)]` `= 15 sin (2 pi t + phi)` where `tan phi = sqrt8` whose amplitude `a_(2) is 15 units`. Therefore , the required ratio `= (a_(1))/(a_(2)) = (10)/(15) = (2)/(3)` |
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