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If two vertices of a triangle are (1,3) and (4,-1) and the area of triangle is 5 sq. units, then the angle at the third vertex lies in : |
Answer» `A=1/2*b*h` `5=1/2*5*h` `h=2 unit` from diagram AC=BC AD=Db=5/2 `tantheta=(5/2)/2=5/4` `theta=tan^(-1)5/4` `/_C=2tan^(-1)5/4` `C in (0,2tan^(-1)5/4)`. option a is correct. |
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