If V is the volume of a cuboid of dimensions a,b,c and S is its surface area then prove that = \frac{2}{S}(\frac{1}{a}+\frac{1}{b}+\frac{1}{c} ★Also the Question is in the attachment.★Please don't spam :-/

If V is the volume of a cuboid of dimensions a,b,c and S is its surfac

1.	If V is the volume of a cuboid of dimensions a,b,c and S is its surface area then prove that = \frac{2}{S}(\frac{1}{a}+\frac{1}{b}+\frac{1}{c} ★Also the Question is in the attachment.★Please don't spam :-/
Answer» <html><body><p>The dimensions of the <a href="https://interviewquestions.tuteehub.com/tag/cuboid-428294" style="font-weight:bold;" target="_blank" title="Click to know more about CUBOID">CUBOID</a> are a,b,c.We know that, Volume of the cuboid V=abc and surface area of the cuboid S=2(ab+bc+ac)To prove: V1 = S2 [ <a href="https://interviewquestions.tuteehub.com/tag/a1-360230" style="font-weight:bold;" target="_blank" title="Click to know more about A1">A1</a> + <a href="https://interviewquestions.tuteehub.com/tag/b1-388995" style="font-weight:bold;" target="_blank" title="Click to know more about B1">B1</a> + c1 ]Consider LHS, V1 = abc1 ...(1)Consider RHS.S2 [ a1 + b1 + c1 ]= 2(ab+bc+ac)2 [ a1 + b1 + c1 ] = ab+bc+ac1 [ a1 + b1 + c1 ] = ab+bc+ac1 [ abcab+bc+ac ] = abc1 S2 [ a1 + b1 + c1 ]= abc1 ...(2)Hence from (1) and (2) we get V1 = S2 [ a1 + b1 + c1 ] now <a href="https://interviewquestions.tuteehub.com/tag/mark-555248" style="font-weight:bold;" target="_blank" title="Click to know more about MARK">MARK</a> me as <a href="https://interviewquestions.tuteehub.com/tag/brainliest-1995348" style="font-weight:bold;" target="_blank" title="Click to know more about BRAINLIEST">BRAINLIEST</a> and follow me</p></body></html>