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If values of `Delta_(f)H^(Theta)` of `ICI(g),CI(g)`, and `I(g)` are, respectively, `17.57,121,34`, and `106.96 J mol^(-1)`. The value of `I-CI` (bond energy) in `J mol^(-1)` isA. `17.57`B. `210.73`C. `35.15`D. `106.96` |
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Answer» The process will be `I(g) +CI(g) rarr I-CI(g),DeltaH^(Theta) = 17.57J mol^(-1)` `DeltaH^(Theta) =` Heat of atomisation of `I(g)` and `CI(g)`-Bond enegry of `I-CI` bond `17.51 = 121.34 +106.96-x` `x = 210.73 J mol^(-1)` |
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