1.

If values of Lambda_(0) of NH_(4)Cl , NaOH and NaCl are 130 , 127 and 109 Omega^(-1) cm^(2) eq^(-1) respectively . The Lambda_(NH_(4)OH)^(@) inOmega^(-1) cm^(2) eq^(-1) is

Answer»

456
238
196
22

Solution :`Lambda_(NH_(4)OH)^(@)= Lambda_(NH_(4)CL)^(@) + Lambda_(NaOH)^(@) - Lambda_(NaCl)^(@)`
`= 130 + 217 - 109`
`= +238 Omega cm^(2) eq^(-1)`


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