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If `vec(A) = 2 I + j - k , vec(B) = I + 2 j + 3 k` , and `vec(C ) = 6 i - 2 j - 6 k`,then the angle between `(vec(A) + vec(B))` and `vec(C )` will beA. `30^(@)`B. `45^(@)`C. `60^(@)`D. `90^(@)` |
Answer» Correct Answer - D `vec(A) + vec(B) = vec(D) = 3 i + 3j + 2k` `vec(C ) = 6 i - 2j - 6k` `vec(D) . Vec(C ) = 18 - 6 - 12 = 0` `theta = 90^(@)` |
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