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If vec(A)=2hati + 3hatj and vec(B)=hati + hatj, then the vector component of vec(A) in the direction of vec(B) is : |
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Answer» `(hati + HATJ)` `ACOSTHETA=((Acostheta)B)/B` `=(ABcostheta)/B=(vec(A).vec(B))/B=(vec(A)vec(B))/B(vec(B)/B)` `=5/sqrt(2)(hati+hatj)/sqrt(2)=2.5(hati+hatj)` |
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