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If ` vec a`and ` vec b`are two vectors such that `| vec a|=4,| vec b|=3`and ` vec adot vec b=6`. Find the angle between ` vec a`and ` vec b`. |
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Answer» We know, `veca*vecb = |veca|*|vecb|cos theta` Putting given values, `6 = 4*3*costheta` `=>cos theta = 1/2` `=>theta = 60^@` So, the angle between `veca` and `vecb` is `60^@`. |
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