1.

If vec(A).vec(B)=|vec(A)xxvec(B)|, then the resultant of vec(A) and vec(B) is:

Answer»

`vec(A) + vec(B)`
`vec(A)-vec(B)`
`SQRT(A^(2)+B^(2))`
`sqrt(A^(2) + B^(2) + sqrt(2)AB)`

SOLUTION :`|vec(A).vec(B)|=|vec(A)xxvec(B)|`
`IMPLIES costheta=sinthetaimplies theta=45^@`
`:. R=sqrt(A^(2) + B^(2) + 2AB cos45^@)`
`R=sqrt(A^(2) + B^(2) + sqrt(2)AB)`


Discussion

No Comment Found

Related InterviewSolutions