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If `|vec(A)xxvec(B)|=sqrt(3)vec(A).vec(B)`, then the value of `|vec(A)+vec(B)|` isA. `(A^(2) + B^(2) + (AB)/(sqrt(3)))^(1//2)`B. `A + B`C. `(A^(2) + B^(2) + sqrt(3) AB)^(1//2)`D. `(A^(2) + B^(2) + AB)^(1//2)` |
Answer» Correct Answer - D `|vec(A) xx vec(B)| = sqrt(3) vec(A) . Vec(B)` `AB sin theta = sqrt(3) AB cos theta` `tan theta = sqrt(3) rArr theta = 60^(@)` `|vec(A) + vec(B)| = sqrt(A^(2) + B^(2) + 2 AB cos 60^(@))` ` = (A^(2) + B^(2) + AB )^(1//2)` |
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