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If `vecA=3hati+4hatj` and `vecB=7hati+24hatj`, find a vector having the same magnitude as `vecB` and parallel and same direction as `vecA`. |
Answer» The vector parallel to `vecA` and having magnitude of `vecB` is `vecC=|vecB|hatA` `B=sqrt(7^(2)+24^(2))=25` `hatA=(vecA)/(A)=(3hati+4hatj)/sqrt(3^(2)+4^(2))=(1)/(5)(3hatj+4hatj)` `vecC=25xx(1)/(5)(3hati+4hatj)=15hati+20hatj` |
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