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If `veca and vecb` are non-collinear vectors and `vecA= (p+4q)veca+ (2p+q+1)vecb and vecB= (-2p+q+2)veca+ (2p-3q-1)vecb`, and if `3vecA= 2vecB`, then determine `p and q`. |
Answer» Putting the values of `vecA and vecB`, and then equating the coefficients of `veca and vecb` on both sides, we get `" "3(p+4q) = 2(-2p+q+2)` `" "3(2p+q+1)= 2(2p-3q-1)` `" "7p+10q=4 and 2p+9q=-5` Solving, we get `p=2 and q=-1` |
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