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If `veca, vecb` and `vecc` are position vectors of A,B, and C respectively of `DeltaABC` and `if|veca-vecb|=4,|vecb-vec(c)|=2, |vecc-veca|=3`, then the distance between the centroid and incenter of `triangleABC` isA. 1B. `1/2`C. `1/3`D. `2/3` |
Answer» Correct Answer - C Let G be centroid and I be incenter. `|vec(GI)|=|vec(OI)-vec(OG)|=|(2veca+3vecb+4vecc)/(9)-(veca+vecb+vecc)/(3)|` `=|(-veca+vecc)/(9)|=3/9=1/3` |
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