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If `|vecA+vecB|=|vecA|+|vecB|`, then angle between `vecA` and `vecB` will beA. `90^@`B. `120^@`C. `0^@`D. `60^@` |
Answer» Correct Answer - B `|vecA+vecB|^2=A^2+B^2+2AB cos theta` `rArr A^2=A^2+A^2+2A^2 cos theta` `rArr cos theta =-1/2 rArr theta=120^@` |
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