If vecB_(1),vecB_(2) and vecB_(3) are the magnetic field due to l_(1),l_(2) and l_(3), then in Ampere's circuital law ointvecB.vec(dl)=mu_(0)l, vecB is

If vecB_(1),vecB_(2) and vecB_(3) are the magnetic field due to l_(1),

1.	If vecB_(1),vecB_(2) and vecB_(3) are the magnetic field due to l_(1),l_(2) and l_(3), then in Ampere's circuital law ointvecB.vec(dl)=mu_(0)l, vecB is
Answer» `vecB=vecB_(1)-vecB_(2)` `vecB=vecB_(1)+vecB_(2)+vecB_(3)` `vecB=vecB_(1)-vecB_(2)+vecB_(3)` `vecB=vecB_(3)` ANSWER :B

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If vecB_(1),vecB_(2) and vecB_(3) are the magnetic field due to l_(1),l_(2) and l_(3), then in Ampere's circuital law ointvecB.vec(dl)=mu_(0)l, vecB is

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