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If vector a and vector b are vectors such that |vector a| = 2, = |vector b| = 7 and vector(a x b) = 3i + 2j + 6k, then what is the acute angle between vector a and vector b ? a. 30° b. 45° c. 60° d. 90° |
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Answer» Correct option a. 30° Explanation: sinθ = vector(|a x b|)/(|vector a||vector b|) = 7/2 x 7 = 1/2 ⇒ θ = 30° |
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