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If vector F = i + 3j+ 2k acts on a particle to displace it from the point A(i + 2j− 3k) to the point B(3i − j + 5k). The work done by the force will be A. 5 units B. 7 units C. 9 units D. 10 units |
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Answer» Correct option C. 9 units Explanation: The line joining the points vector A(i + 2j – 3k) and vector B(3i – j + 5k) is i.e., vector AB = 2i – 3j +8k Work done = vector (F.AB) = 1×2 + 3×(-3) + 2 × 8 = 9 |
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