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If water contains 10 ppm of `MgCl_2` and 8 ppm of `CaSO_4`, calculate the ppm of `CaCO_3`. |
Answer» `MgCl_(2)=(10xx100)/(65)=10.53ppm`, `CaSO_(4)=(8xx100)/(136)=5.92ppm` `ppm of CaCO_(3)=10.53+5.92=16.45ppm`. |
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