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If wavelength of incident light for Rayleigh scattering is decreased from 8000 Å to 4000 Å, then intensity of scattered light will become ...... times then that of initial intensity. |
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Answer» Solution :`I=(I)/(lambda4)` `(I_2)/(I_1)=(lambda_1)/(lambda_2)^4` `THEREFORE I_2=I_1xx((8000)/(4000))^4` `=I_1xx(2)^4` `=16I_1` |
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