InterviewSolution
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InterviewSolution
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If we express the energy of a photon in `KeV` and the wavelength in angstroms , then energy of a photon can be calculated from the relationA. `E = 12.4 hv`B. `E = 12.4 h//lambda`C. `E = 12.4// lambda`D. `E = hv` |
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Answer» Correct Answer - C Energy of photon `E = (hc)/( lambda) (joules) = (hc)/( e lambda) ( eV)` `rArr E( eV) = (6.6 xx 10^(-34) xx 3 xx 10^(8))/(1.6 xx 10^(-19) xx lambda(Å)) = (12375)/(lambda (Å))` `rArr E(keV) = (12.37)/( lambda (Å)) ~~ (12.4)/(lambda)` |
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