If we have 3 resistors of 1k, 2k and 3k, how should they be used amongst R1, R2 and R3 to get the maximum gate voltage in the following C.S. stage?(a) R1 = 1k, R2 = 2k, R3 = 3k(b) R1 = 3k, R2 = 2k, R3 = 1k(c) R1 = 2k, R2 = 1k, R3 = 3k(d) R1 = 3k, R2 = 1k, R3 = 2kI got this question in exam.The origin of the question is MOSFET Amplifier with CS Configuration in section FET Amplifiers of Analog Circuits

If we have 3 resistors of 1k, 2k and 3k, how should they be used among

1.	If we have 3 resistors of 1k, 2k and 3k, how should they be used amongst R1, R2 and R3 to get the maximum gate voltage in the following C.S. stage?(a) R1 = 1k, R2 = 2k, R3 = 3k(b) R1 = 3k, R2 = 2k, R3 = 1k(c) R1 = 2k, R2 = 1k, R3 = 3k(d) R1 = 3k, R2 = 1k, R3 = 2kI got this question in exam.The origin of the question is MOSFET Amplifier with CS Configuration in section FET Amplifiers of Analog Circuits
Answer» Right answer is (a) R1 = 1k, R2 = 2k, R3 = 3k The best EXPLANATION: The Thevenin resistance SEEN by V1 is R1 + (R2 \|\| R3). The gate voltage is a result of V1 going through a potential divider of R1 and (R2 \|\| R3) where the voltage ACROSS (R2 \|\| R3) is essentially the gate voltage ie V1 * [(R2 \|\| R3) / { R1 \|\| R2 \|\| R3) }]. Hence, we need to maximize (R2 \|\| R3) which is possible if R2=2k and R3=3k. This implies R1 has to be equal to 1k.

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