1.

If we mix 50 ml 0.2 M FeCl_(3) and50 ml 0.4 M NaOH, then what mass of Fe(OH)_(3) (in gm) will precipitale.

Answer»

`0.356 gm`
`0.713 gm`
`7.13 gm`
`1.07 gm`

Solution :`{:(FeCl_(3) +,3 Na OH,rarr,Fe (OH)_(3),+,3 NaCL,),(10 xx 10^(-3) " mole",20 xx 10^(-3) " mole",,,,,),(NaOH "is" LR,,,,,,):}`
`n_(Fe (OH)_(3))` FORMED `= (20)/(3) xx 10^(-3)` mole
Mass of `Fe(OH)_(3) = (20)/(3) xx 107 xx 10^(-3)`
`= 0.713 gm`


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