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If x> 0, then the expression `x^100/(1 + x + x^2 + x^3 .....x^200)` is always less than or equal to |
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Answer» `AM>=GM` `(1+x+x^2+x^3+x^4...X^200)/201>=(11*x^2*x^3...x^200)^(1/201)` `1/201>=(x^((200+201)/2))^(1/201)/(1+x+x^2+...+x^200)` `1/201>=x^100/(1+x+x^2+...+x^200)` option 1 is correct. |
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