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if `x=(1+t)/t^3 ,y=3/(2t^2)+2/t` satisfies `f(x)*{(dy)/(dx)}^3=1+(dy)/(dx)` then `f(x)` is:A. `x`B. `(x^(2))/(1+X^(2))`C. `x+x+(1)/(x)`D. `x-(1)/(x)` |
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Answer» Correct Answer - A `(dy)/(dx)=(dy//dt)/(dx//dt)=(-((3+2r))/(t^(3)))/(-((3+2t))/(t^(4)))=t` Since `f(x)((dy)/(dx))^(3)=1+(dy)/(dx)` `rArr" "f(x)t^(3)=1+t` `rArr" "f(x)=(1+t)/(t^(3))=x` |
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