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Answer» Correct Answer - 1 Since `1+2z+3x^(2)+4x^(3)+"……"oo= (1+x)^(2)`, we have `(1+2x+3x^(2)+4x^(3)+"……"oo)^(1//2) = [(1-x)^(-2)]^(1//2)` `= (1-x)^(-1)` `= 1+x+x^(2)+"…."+x^(n) + "…."oo` Therefore, the coefficient of `s^(n)` is `1`. |
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