1.

If (x + 1)(x + 2) …(x + n) = A_0 + A_1 x + ….+ A_n x^n then A_1 + 2A_2 + ….+ nA_n =

Answer»

`(N+1)! [1/2 + 1/3+ ....+ 1/(n + 1)]`
`n! [1/2 + 1/3+ ....+ 1/(n + 1)]`
`(n+1)! [1 + 1/3+ ....+ 1/(n + 1)]`
`n! [1 +1/2 + 1/3+ ....+ 1/(n + 1)]`

ANSWER :A


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