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If x-1/x=5 , then x^3-1/x^3 = 1) 1002) 1253) 1404) 145

Answer»

ANSWER:

→ 140

GivEn :-

  • \sf \: x -  \dfrac{1}{x}  = 5

To Find :-

  • \sf \: value \: of \:  {x}^{3}  -  \dfrac{1}{ {x}^{3} }

Step-by-step explanation:

\sf \: x -  \dfrac{1}{x}  = 5

\implies \:  \sf \: (x -  \dfrac{1}{x})^{2}   = {5}^{2}

(By squaring both SIDES..)

\implies \sf \:  {x}^{2}  +  \dfrac{1}{ {x}^{2} }  - 2 \times x \times  \dfrac{1}{x}  = 25

\implies \sf \:  {x}^{2}  +  \dfrac{1}{ {x}^{2} }  - 2    = 25

\implies \sf \:  {x}^{2}  +  \dfrac{1}{ {x}^{2} }    = 25 + 2

\implies \sf \:  {x}^{2}  +  \dfrac{1}{ {x}^{2} }    = 27

Now,

\sf \:   {x}^{3}  -  \dfrac{1}{ {x}^{3} }

\implies \sf \: (x -  \dfrac{1}{x} )( {x}^{2}  +  \dfrac{1}{ {x}^{2} }   +  x \times  \dfrac{1}{x} )

(PUTTING the VALUES)

\implies \sf \: 5 \times (27 + 1)

\implies \sf \: 5 \times 28

\implies  \boxed{ \red{\sf \:   {x}^{3}  -  \dfrac{1}{ {x}^{3} }  = 140}}



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