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If `x=111"...."(20 digits),y=333"...."(10digits) and z=222".....2"(10 digits), then (x-y^(2))/(z)` equals.A. `(1)/(2)`B. 1C. 2D. 4 |
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Answer» Correct Answer - B `:.x=(1)/(9)(999"...."9)=(1)/(9)(10^(20)-1)` `y=(1)/(3)(999"...."9)=(1)/(3)(10^(10)-1)` and `z=(2)/(9)(999"...."9)=(2)/(9)(10^(10)-1)` `:.(x-y^(2))/(z)=((1)/(9)(10^(20)-1)-(1)/(9)(10^(10)-1)^(2))/((2)/(9)(10^(10)-1))` `=(10^(10)+1-(10^(10)-1))/(2)=1` |
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