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IF `[x^(2) - 2x + a]=0` has no solution, then find the values of a (where `[*] ` represents the greatest integer). |
Answer» We have `[x^(2) - 2x + a]=0` `rArr x^(2) - 2x + a in` [ 0, 1) So, equation has no solution if `x^(2) - 2x a notin` [0, 1). `therefore x^(2) - 2x + a lt AA x in` R, which is not possible. So, `x^(2) - 2x + a lt 1 AA x in` R `rArr x^(2) - 2x + a - 1 ge 0, AA x in` R Now, `Dge 0` `rArr 4-4 (a- 1) le 0` `rArr 2 - a le 0` `rArr a ge 2` `rArr a in [ 2, infty)` |
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