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If `[x]^2- 5[x]+6= 0`, [x] denote the greatest integer function, thenA. `x in[3,4]`B. `x in (2,3]`C. `x in [2,3]`D. `x in [2,4]` |
Answer» Correct Answer - C We have `[x]^(2)-5[x]+6=0` `rArr [x]^(2)-3[x]-2[x]+6=0` `rArr [x]([x]-3)-2([x]-3)=0` `rArr([x)-3)([x]-2)=0` `rArr [x]=2,3]` `:. "x" in[2,3]` |
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