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If x-2 = 64, then x 1/3 + x0 = A. 2 B. 3 C. 3/2 D. 2/3 |
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Answer» \((\cfrac{1}{8})^2\) = (8)2 \(\cfrac{1}{x}\) = 8 x = \(\cfrac{1}{8}\) x1/3 + xo = \((\cfrac{1}{8})^{\cfrac{1}{3}}\) + \((\cfrac{1}{8})^0\) = \(\cfrac{1}{2} + 1\) = \(\cfrac{3}{2}\) |
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