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If x^2+y^2=10 and xy=3,find the value of (x+y) and (x-y) I want the Ans Now right ans will be mark as brainleniest |
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Answer» Step-by-step EXPLANATION:(x^2 - y^2) = 10...(1) (x + y) = 2...(2) We KNOW that (x + y)^2 = x^2 + y^2 + 2xy (2) => x + y = 2 => (x + y)^2 = 4 => x^2 + y^2 + 2xy = 4 Also from (1) (x^2 - y^2) = 10 So we have x^2 + y^2 + 2xy - x^2 + y^2 = 4 - 10 => 2Y^2 + 2xy = -6 => 2y(x+y) = -6 => 2y(2) = -6 => y = -3/2 x + y = 2 => x - 3/2 = 2 => x = 2 + 3/2 => x = 7/2 Therefore x = 7/2 and y = -3/2 (x+y)= 2 and (x-y)= 5 |
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