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If `x^2 + y^2=6xy` prove that `2log(x+y) = logx+ logy + 3log2` |
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Answer» `x^2+y^2 = 6xy` `=>(x+y)^2-2xy = 6xy` `=>(x+y)^2 = 8xy` Taking log both sides, `log(x+y)^2 = log(8xy)` `=>2log(x+y) = log8+logx+logy` `=>2log(x+y) = log2^3+logx+logy` `=>2log(x+y) = 3log2+logx+logy` |
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