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If x+2y=9 and xy=7, find the value of x²+4y². |
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Answer» Step-by-step explanation:sincexy=7 so x=7/y a/q x+2Y=9 or 7/y+2y=9 or 2y^2+9y+7=0 or 2y ^2+7y +2y +7=0 or y(2y+7)+1(2y+7)=0 or (y+1)(2y+7)=0 so y=-1,-7/2 if y=-1 then x=7/(-1)=-7 if y=-7/2 then x=14/(-7)=-2 |
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