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If (x – 3)2 + (y – 5)2 + (z – 4)2 = 0, Then The Value Of X2/9 + Y2/25 + Z2/16 Is |
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Answer» (x – 3)2 + (y – 5)2 + (Z – 4)2 = 0 ⇒ x – 3 = 0 ⇒ x= 3 Y – 5 = 0 ⇒ y = 5 Z – 4 = 0 ⇒ z = 4 (x – 3)2 + (y – 5)2 + (z – 4)2 = 0 ⇒ x – 3 = 0 ⇒ x= 3 Y – 5 = 0 ⇒ y = 5 Z – 4 = 0 ⇒ z = 4 |
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