1.

If `X = 3 - 4t^(2) + t^(3)`, then work done in first 4s. will be (Mass of the particle is 3 gram) :A. 384 mJB. 168 mJC. 192 mJD. None of these

Answer» Correct Answer - A
Work energy theorem
`W = DeltaKE`
`x=3-4t^(2)+t^(3)`
`v=(dx)/(dt)=-8t+3t^(2)`
`v_(1)(t=0)=0`
`v_(2)(t=4)=16`
Therefore,`DeltaKE=1/2mv_(2)^(2)-1/2mv_(1)^(2)`
=`1/2xx3xx10^(-3)xx16xx16-0=384mJ`


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