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| 1. |
If x=3and y=2,then the value of (x-y)(x^2+xy+y^2) |
| Answer» X + y)² = x² + y² + 2xy = (3√8)² = 72 ……..(1) (x - y) ² = x² + y² -2xy = (√2)² = 2 ………..(2) EQ(1) - eq(2) = 4xy = 70 => 2xy = 35 => 8XY = 140 …………(3) (x + y)² = x² + y² +2xy => x² + y² = (x+y)² - 2xy => x² + y² = 72 - 35 = 37 ………….(4) Now, by multiplying (3) & (4) We get, 8xy ( x² + y² ) = 140 x 37 = 5180Step-by-step explanation: | |