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If X 40 41 is a Pythagorean triplet what is the value of x ​

Answer» N :-Let's :-HYPOTENUSE = 41Base = 40Perpendicular = xBy USING Pythagoras theorem⇒ H² = B² + P²⇒ ( 41 )² = ( 40 )² + x²⇒ 1681 = 1600 + x²⇒ x² = 1681 - 1600⇒ x² = 81⇒ x = √81⇒ x = 9Value of x is 9


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