If x+7 ,x+11 , 19+x are in successive proportion then x =

1.	If x+7 ,x+11 , 19+x are in successive proportion then x =
Answer» *Question:— If x+7 ,x+11 , 19+x are in successive proportion then x = *Answer:— x+7 , 11+x , 19+x are in successive proportion. So, → (11 + x)/(x + 7) = (19 + x)/(11 + x) → 121 + 22x + x × x = 133 + 26X + x × x → 4X = -12 → x = -3 Hence our answer is -3 Happy LEARNING. #Be Brainly. $\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: @vikramjeeth$

Answer»

*Question:—

*Answer:—

x+7 , 11+x , 19+x are in successive proportion.

So,

→ (11 + x)/(x + 7) = (19 + x)/(11 + x)

→ 121 + 22x + x × x = 133 + 26X + x × x

→ 4X = -12

→ x = -3

Hence our answer is -3

Happy LEARNING.

#Be Brainly.

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: @vikramjeeth$

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If x+7 ,x+11 , 19+x are in successive proportion then x =​

*Question:—

*Answer:—

So,

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If x+7 ,x+11 , 19+x are in successive proportion then x =