1.

If (x-a) cos theta + y sin theta = (x - a) cos phi + y sin phi = a and tan (theta/2)-tan(phi/2) = 2b then

Answer»

`y^(2) = 2ax - (1-b^(2))X^(2)`
`"TAN" (THETA)/(2) = (1)/(x) (y + bx)`
`y^(2) = 2bx - (1 - a^(2))x^(2)`
`"tan" (PHI)/(2) = (1)/(x) (y - bx)`

Answer :A::B::D


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