1.

If x = a sec^2 theta, y = aTan^3 theta then (d^3y)/(dx^3) =

Answer»

`(-3)/(8a^2)COT^3theta`
`(3)/(8a^2)cot^3theta`
`3 sec^2 theta tan theta`
`3/(4A)cot theta`

ANSWER :A


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