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If `X`and `Y`are `2xx2`matrices, then solvethe following matrix equations for `X`and `Ydot``2X+3Y=[2 3 4 0]`, `3X+2Y=[-2 2 1-5]` |
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Answer» We have, ` 2X+3Y=[{:(2,3),(4,0):}]` and `3X+2Y=[{:(-2,2),(1,-5):}]` On subtracting Eq. i from Eq. ii we get `therefore (3X+2Y)-(2X_3Y)=[{:(-2,-2,2-3),(1-4,-5,0):}]` `(X-Y)=[{:(-4,-1),(-3,-5):}]` On adding Eqs. I and ii, we get `( 5X+5Y)=[{:(0,5),(5,-5):}]` `rArr (X+Y)=(1)/(5)[{:(-2,0),(-2,-6):}]` `therefore X=[{:(-2,0),(-1 ,-3):}]` From Eq. iv, `[{:(-2,0),(-1,-3):}]+y=[{:(0,1),(1,-1):}]` `therefore Y=[{:(2,1),(2,2):}]` and ` X=[{:(-2,0),(-1, -3):}]` |
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