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If `X and Y` are two non-empty sets where `f: X->Y`,is function is defined such that`f(c) = {f (x): x in C}` for `C sube X and f^-1 (D) = {x: f(x) in D}` for `D sube Y`,for any `A sube Y and B sube Y`, thenA. `f^(1){f(A)}=A`B. `f^(1){f(A)}=A," only if "f(X)=Y`C. `f{f^(-1)(B)}, " only if " B sube f(x)`D. `f{f^(-1)(B)}=B` |
Answer» Correct Answer - C Since, only (c) satisfy given definition i.e. `f{f^(-1)(B)}=B` Only,if `B sube f(x)` |
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